June Park (Q1434576)

Summary from English Wikipedia (enwiki)

June Park is a census-designated place (CDP) in Brevard County, Florida. The population was 4,283 at the 2020 United States census, up from 4,094 at the 2010 United States Census. It is part of the Palm Bay–Melbourne–Titusville, Florida Metropolitan Statistical Area.

Summary from Español / Spanish Wikipedia (eswiki)

June Park es un lugar designado por el censo ubicado en el condado de Brevard en el estado estadounidense de Florida. En el Censo de 2010 tenía una población de 4.094 habitantes y una densidad poblacional de 465,6 personas por km².[2]

Wikidata location: 28.0736, -80.6858 view on OSM or edit on OSM

matches

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found 2 match candidates

relation: June Park (OSM)exact location match [show tags]
name: June Park
place: locality
source: TIGER/Line® 2008 Place Shapefiles (http://www.census.gov/geo/www/tiger/)
boundary: census
tiger:reviewed: no
way: June Park (OSM), 0.61 miles from Wikidata [show tags]
name: June Park
source: TIGER/Line® 2008 Place Shapefiles (http://www.census.gov/geo/www/tiger/)
boundary: census
wikidata: Q1434576
tiger:CPI: N
wikipedia: en:June Park, Florida
tiger:LSAD: 57
tiger:NAME: June Park
tiger:MTFCC: G4210
tiger:CLASSFP: U1
tiger:PCICBSA: N
tiger:PLACEFP: 35800
tiger:PLCIDFP: 1235800
tiger:STATEFP: 12
tiger:FUNCSTAT: S
tiger:NAMELSAD: June Park CDP
tiger:PCINECTA: N
tiger:reviewed: no
gnis:feature_id: 2402636

wikidata match: Q1434576

Search criteria from Wikidata

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census-designated place in the United States (Q498162) boundary=census
administrative territorial entity (Q56061) boundary=administrative