[timeout:300][out:json];
(
node(around:1000,38.95640,-85.89000)[boundary=administrative][~"^(addr:housenumber|.*name.*)$"~".",i];
way(around:1000,38.95640,-85.89000)[boundary=administrative][~"^(addr:housenumber|.*name.*)$"~".",i];
rel(around:1000,38.95640,-85.89000)[boundary=administrative][~"^(addr:housenumber|.*name.*)$"~".",i];
node(around:1000,38.95640,-85.89000)["operator:type"="government"][~"^(addr:housenumber|.*name.*)$"~".",i];
way(around:1000,38.95640,-85.89000)["operator:type"="government"][~"^(addr:housenumber|.*name.*)$"~".",i];
rel(around:1000,38.95640,-85.89000)["operator:type"="government"][~"^(addr:housenumber|.*name.*)$"~".",i];
node(around:1000,38.95640,-85.89000)[place=city][name];
way(around:1000,38.95640,-85.89000)[place=city][name];
rel(around:1000,38.95640,-85.89000)[place=city][name];
node(around:1000,38.95640,-85.89000)[place=municipality][name];
way(around:1000,38.95640,-85.89000)[place=municipality][name];
rel(around:1000,38.95640,-85.89000)[place=municipality][name];
);
out center tags;
Seymour is a city in Jackson and Redding Townships, Jackson County, Indiana, United States. It is situated about 62 miles (100 km) south of Indianapolis and 55 miles (89 km) north of Louisville, Kentucky. Its population was 21,569 at the 2020 census.
Seymour es una ciudad ubicada en el condado de Jackson en el estado estadounidense de Indiana. En el Censo de 2010 tenía una población de 17.503 habitantes y una densidad poblacional de 591,4 personas por km².[3]
found a single match candidate
| municipality (Q15284) | place=municipality |
| government organization (Q2659904) | operator:type=government |
| locality (Q3257686) | place=locality |
| city (Q515) | place=city |
| administrative territorial entity (Q56061) | boundary=administrative |
| Cities in Indiana | place=city |
| Cities in Jackson County, Indiana | place=city |