[timeout:300][out:json];
(
node(around:1000,41.54667,-87.26472)["political_division"][~"^(addr:housenumber|.*name.*)$"~".",i];
way(around:1000,41.54667,-87.26472)["political_division"][~"^(addr:housenumber|.*name.*)$"~".",i];
rel(around:1000,41.54667,-87.26472)["political_division"][~"^(addr:housenumber|.*name.*)$"~".",i];
node(around:1000,41.54667,-87.26472)[boundary=administrative][~"^(addr:housenumber|.*name.*)$"~".",i];
way(around:1000,41.54667,-87.26472)[boundary=administrative][~"^(addr:housenumber|.*name.*)$"~".",i];
rel(around:1000,41.54667,-87.26472)[boundary=administrative][~"^(addr:housenumber|.*name.*)$"~".",i];
node(around:1000,41.54667,-87.26472)[place=township][name];
way(around:1000,41.54667,-87.26472)[place=township][name];
rel(around:1000,41.54667,-87.26472)[place=township][name];
);
out center tags;
Hobart Township is one of eleven townships in Lake County, Indiana. As of the 2010 census, its population was 39,417 and it contained 16,366 housing units.
El municipio de Hobart (en inglés: Hobart Township) es un municipio ubicado en el condado de Lake en el estado estadounidense de Indiana. En el año 2010 tenía una población de 39417 habitantes y una densidad poblacional de 585,84 personas por km².[2]
found 2 match candidates
| township (Q19610511) | place=township |
| administrative territorial entity (Q56061) | boundary=administrative |
| Townships in Indiana | place=township |
| Townships in Lake County, Indiana | place=township |